= 27¹/³
= (3³)¹/³
= 3³/³
= 3¹
= 3
3. Diketahui [(xⁿ⁻¹ yⁿ)³] / [x²ⁿ y⁶⁺ⁿ] senilai dengan xᵃ yᵇ. Tentukan nilai b/a.
Jawaban:
[(xⁿ⁻¹ yⁿ)³] / [x²ⁿ y⁶⁺ⁿ]
= [x³ⁿ⁻³ y³ⁿ] / [x²ⁿ y⁶⁺ⁿ]
= 27¹/³
= (3³)¹/³
= 3³/³
= 3¹
= 3
3. Diketahui [(xⁿ⁻¹ yⁿ)³] / [x²ⁿ y⁶⁺ⁿ] senilai dengan xᵃ yᵇ. Tentukan nilai b/a.
Jawaban:
[(xⁿ⁻¹ yⁿ)³] / [x²ⁿ y⁶⁺ⁿ]
= [x³ⁿ⁻³ y³ⁿ] / [x²ⁿ y⁶⁺ⁿ]
Editor: Maria Nofianti