b. b 2y⁵ × b³ 6 y²
= b¹⸍² . 2 y⁵ × b³ . 6 y²
= b¹⸍²⁺³. 12 . y⁵⁺²
= b⁷⸍² . 12 . y⁷
= b⁷⸍² 12 y⁷
c. (tn³)⁴ × 4t³
= t⁴ n¹² × 4t³
= 4 n¹² t⁴⁺³
= 4 n¹² t⁷
d. (2x³) × 3(x²y²)³ × 5y⁴
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Senin, 29 April 2024 -
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b. b 2y⁵ × b³ 6 y²
= b¹⸍² . 2 y⁵ × b³ . 6 y²
= b¹⸍²⁺³. 12 . y⁵⁺²
= b⁷⸍² . 12 . y⁷
= b⁷⸍² 12 y⁷
c. (tn³)⁴ × 4t³
= t⁴ n¹² × 4t³
= 4 n¹² t⁴⁺³
= 4 n¹² t⁷
d. (2x³) × 3(x²y²)³ × 5y⁴
Editor: Maria Nofianti
