(ii) 5, 13, 14
14 = √(13² + 5²)
14 = √(169 + 25)
14 ≠ √194 (bukan tripel Pythagoras)
(iii) 7, 24, 25
25 = √(24² + 7²)
25 = √(576 + 49)
25 = √625
25 = 25 (tripel Pythagoras)
(iv) 20, 21, 29
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Kamis, 2 Mei 2024 -
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(ii) 5, 13, 14
14 = √(13² + 5²)
14 = √(169 + 25)
14 ≠ √194 (bukan tripel Pythagoras)
(iii) 7, 24, 25
25 = √(24² + 7²)
25 = √(576 + 49)
25 = √625
25 = 25 (tripel Pythagoras)
(iv) 20, 21, 29
Editor: Yulia Pramuninggar
Sumber: Buku Matematika Kelas 8 Semester 2
